Question

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Answer 1

Answer:

128

Step-by-step explanation:

Answer 2

Answer:

128

Step-by-step explanation:

In triangle ABC,

by pythagorus theorem we get,

H^2=P^2+B^2

H^2=64+144

H^2=208

H=root 208

and in,

Triangle ACD,

by pythagorus theorem we get,

H^2=P^2+B^2

208=P^2+400

p^2=192

p=16

ar(tria ABC)+ar(tria ACD)=ar(Rohmbus ABCD)

ar(Rohmbus ABCD)=8+120

ar(Rohmbus ABCD)=128

Hence proved

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