Question

6 रूट 3 एक्स स्क्वायर प्लस 7 एक्स इक्वल टू थ्री​

Answer 1

Answer:

Step-by-step explanation

6√3x² + 7x - √3 = 0

➠ 6√3x² + 9x - 2x - √3 = 0

➠ 3√3x (2x + √3) - 1 (2x + √3) = 0

➠ (2x + √3) (3√3x - 1) = 0

So, 2x + √3 = 0, or, 3√3x - 1 = 0. I think in place of equal to 3 it should be root 3.