Question

6. Ram treated a lustrous, divalent element M with sodium hydroxide. He observed the formation of bubbles in the reaction mixture. He made the same observations when this element was treated with hydrochloric acid. Suggest how can he identify the gas produced. Write chemical equations for both the reactions.​

Answer 1

Answer:

Iqbal treated a lustrous, divalent element M with sodium hydroxide. He observed the formation of bubbles in reaction mixture. ... Hence, hydrogen gas is most likely to be produced during these reactions. The evolution of hydrogen gas can be checked by bringing a burning matchstick or splinter near the evolved gas.

Explanation:

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Answer 2

Answer:

2M + 2NaOH = 2Na(M) + H2

2M + 2HCL = 2M Cl + H2

Explanation:

Lustrous element. = Metal

WKT Metal + Acid/ Base = salt + h2

To identify the gas, he can bring a burning matchstick near the test tube. It burns with a pop sound which indicates the presence of h2 gas.