Question

6.
Ranjan borrowed 80,000 at 15% p.a. compounded annually for 2 years and 3 months. Find the
amount due at the end of the period.
​

Answer 1

Answer:

80000*(15/100)^9/4 solve you got ans.

ans is

Answer 2

$\huge\red{\underline{✪Solution}}$

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7th

Maths

Comparing Quantities

Simple Interest

Rajan borrowed Rs.5000 at 8...

MATHS

Rajan borrowed Rs.5000 at 8% p.a. for 3 years. Find the difference between compound interest simple interest, assuming compounded annually.

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ANSWER

Principal = Rs.5000

Time =3 years

rate = 8%

SI=PRT/100

=5000×8×3/100

SI=1200

Amount compounded Annually

=5000(

100

1+8

)

3

=5000(

100

108

)

3

=

1000000

6298560000

=Rs6298.56

CI=6298.56−5000=Rs.1298.56

Difference between interest

=1298.56−1200=Rs.98.56