Question

6 root 3 + 1 divided by 4 root 2​

Answer 1

$\mathfrak{\huge{\orange{Solution:-}}}$

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$\frac{6 \sqrt{3 } + 1 }{4 \sqrt{2} } \times \frac{4 \sqrt{2} }{4 \sqrt{2} }$

$= > \frac{(6 \sqrt{3})(4 \sqrt{2} ) + 4 \sqrt{2} }{(4 \sqrt{2}) ^{2} }$

$= > \frac{24 \sqrt{6} + 4 \sqrt{2} }{32}$

$= > \frac{6 \sqrt{6} + \sqrt{2} }{8}$