Math, asked by harman9991, 11 months ago

6 + root 3 x square + 7 x is equals to root 3 solve by factorization method

Answers

Answered by IIsahzadiII

Answer:

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$\sqrt{3}x^2 +10 +7 \sqrt{3} = (x +\squr{3}) ( \squr{3}x + 7)$

$\sqrt{3}x^2 + 10x + 7\sqrt{3}$

split the middle term

then we get,

$\sqrt{3}x^2 + 3x + 7x + 7\sqrt{3}\\\sqrt{3}x^2 + (\sqrt{3} \times\sqrt{3}x + 7x + 7\sqrt{3}\\\sqrt{3}x ( x + \sqrt {3}) +7 (x + \sqrt{3})\\(x +\sqrt{3}) (\sqrt{3}x + 7)$

Therefore, 6 +√3x^2 + 7x =(x + √3) (√3x + 7).

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