Question

6 root 3 x square minus 4 root 3 x minus 2 root 3 factorise​

Answer 1

$6 \sqrt{3} {x}^{2} - 4 \sqrt{3} x - 2 \sqrt{3} = 0 \\ 3 {x}^{2} - 2x - 1 = 0 \\ 3 {x}^{2} - 3x + x - 1 = 0 \\ 3x(x - 1) + 1(x - 1) = 0 \\ (x - 1)(3x + 1) = 0 \\ x - 1 = 0 \: or \: 3x + 1 = 0 \\ x = 1 \: or \: x = - \frac{1}{3}$