Math, asked by nanditareym, 1 year ago

6 root 5x^2-9x-3root 5 =0

Answers

Answered by mysticd

Hi ,

6√5x² - 9x - 3√5 = 0

6√5x² - 15x + 6x - 3√5 = 0

6√5x² - 3√5 ×√5 x + 2 × 3x - 3√5 = 0

3√5x ( 2x - √5 ) + 3( 2x - √5 ) = 0

( 2x - √5 ) ( 3√5x + 3 ) = 0

2x - √5 = 0 or 3√5x + 3 = 0

2x = √5 or 3√5x = - 3

x = ( √5 )/2 or x = - 3/(3√5)

x = (√5)/2 , or x = - 1/√5

I hope this helps you.

: )

abhi569: Because he was the first, who checked this question

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abhi569: Its my pleasure,

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abhi569: Sorry for giving wrong information, it was reserved by sir ji [ramanujami] , he told me

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Answered by abhi569

6√5x² -9x -3√5 = 0

6√5x² -(15-6)x -3√5 =0

6√5x² -15x +6x -3√5 =0

3√5x(2x -√5) + 3(2x -√5)=0

(2x-√5)(3√5x+3) =0

By Zero product rule,

2x -√5 = 0 Or 3√5x+3=0

2x = √5 Or 3√5x = -3

x =√5/2 Or x = -3/3√5

x = √5/2 Or x = -1/√5

x =√5/2 Or x = -√5/5

Possible values of x,

√5/2 and -√5/5

I hope this will help you

-by ABHAY

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