6 root 5x^2-9x-3root 5 =0
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Answered by
14
Hi ,
6√5x² - 9x - 3√5 = 0
6√5x² - 15x + 6x - 3√5 = 0
6√5x² - 3√5 ×√5 x + 2 × 3x - 3√5 = 0
3√5x ( 2x - √5 ) + 3( 2x - √5 ) = 0
( 2x - √5 ) ( 3√5x + 3 ) = 0
2x - √5 = 0 or 3√5x + 3 = 0
2x = √5 or 3√5x = - 3
x = ( √5 )/2 or x = - 3/(3√5)
x = (√5)/2 , or x = - 1/√5
I hope this helps you.
: )
6√5x² - 9x - 3√5 = 0
6√5x² - 15x + 6x - 3√5 = 0
6√5x² - 3√5 ×√5 x + 2 × 3x - 3√5 = 0
3√5x ( 2x - √5 ) + 3( 2x - √5 ) = 0
( 2x - √5 ) ( 3√5x + 3 ) = 0
2x - √5 = 0 or 3√5x + 3 = 0
2x = √5 or 3√5x = - 3
x = ( √5 )/2 or x = - 3/(3√5)
x = (√5)/2 , or x = - 1/√5
I hope this helps you.
: )
abhi569:
Because he was the first, who checked this question
Answered by
22
6√5x² -9x -3√5 = 0
6√5x² -(15-6)x -3√5 =0
6√5x² -15x +6x -3√5 =0
3√5x(2x -√5) + 3(2x -√5)=0
(2x-√5)(3√5x+3) =0
By Zero product rule,
2x -√5 = 0 Or 3√5x+3=0
2x = √5 Or 3√5x = -3
x =√5/2 Or x = -3/3√5
x = √5/2 Or x = -1/√5
x =√5/2 Or x = -√5/5
Possible values of x,
√5/2 and -√5/5
I hope this will help you
-by ABHAY
6√5x² -(15-6)x -3√5 =0
6√5x² -15x +6x -3√5 =0
3√5x(2x -√5) + 3(2x -√5)=0
(2x-√5)(3√5x+3) =0
By Zero product rule,
2x -√5 = 0 Or 3√5x+3=0
2x = √5 Or 3√5x = -3
x =√5/2 Or x = -3/3√5
x = √5/2 Or x = -1/√5
x =√5/2 Or x = -√5/5
Possible values of x,
√5/2 and -√5/5
I hope this will help you
-by ABHAY
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