6. Sagar has an urn containing 15 balls. 3 of th
are green, 5 red and 7 white. He picks out on
random, notes the colour and puts it back. T
he again picks out one ball from the bag
random. Draw a tree diagram and find
probability of the following:
(a) both balls are white (b) only one is white c) both ate not white
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49/225 , 112/225 & 64/225 are Probability That (a) both balls are white (b) only one is white c) both ate not white respectively
Step-by-step explanation:
Total Balls = 15
Green Balls= 3
Red Balls = 5
White Balls = 7
Probability of Green Balls = 3/15 = 1/5
Probability of Red Balls = 5/15 = 1/3
Probability of White Balls = 7/15
Probability of not White Ball = 1 - 7/15 = 8/15
Probability that Balls are White = (7/15)(7/15) = 49/225
Probability that only one is white
= (7/15)(8/15) + (8/15)(7/15)
= 112/225
Probability that not white = (8/15)(8/15) = 64/225
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