6. Show that the following points form a equilatera
triangle A(a,0), B(-a, 0), C(0,a (√3)
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Answer:
Given A(a,0) B(−a,0) C(0,a
3
)
AB=
(a−(−a))
2
+(0−0)
2
=
4a
2
=2a
BC=
(0−(−a))
2
+(a
3
)
2
=
4a
2
=2a
CA=
(0−(−a))
2
+(a
3
)
2
=
4a
2
=2a
∴ AB= BC = CA
Hence it is an equilateral triangle
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