Question

6. Simplify a (a2 + a + 1) + 5 and find its value for (i) a = 0, (ii) a = 1 (iii) a = -1.​

Answer 1

Answer:

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Answer 2

Simplification:

$\bold{a( {a}^{2} + a + 1) + 5}$

$\bold{ {a}^{3} + {a}^{2} + a + 5}$

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(i) a=0

${(0)}^{3} + {(0)}^{2} + (0) + 5$

$0 + 0 + 0 + 5$

$\boxed5$

(ii) a=1

${(1)}^{3} + {(1)}^{2} + (1) + 5$

$1 + 1 + 1 + 5$

$\boxed8$

(iii) a=(-1)

${( - 1)}^{3} + {( - 1)}^{2} + ( - 1) + 5$

$( - 1) + (1) + ( - 1) + 5$

$\underline{( - 1) + 1 \: } + ( - 1) + 5$

$0 - 1 + 5$

$\boxed4$