Question

6. Simplify: a(b-c) +b(c-a) + c(a-b)
-​

Answer 1

Step-by-step explanation:

(a−b)(a−c)

1

+

(b−c)(b−a)

1

+

(c−a)(b−c)

1

=

−(a−b)(a−c)(b−c)

−b+c

+

−(a−b)(a−c)(b−c)

−c+a

+

−(a−b)(a−c)(b−c)

−b+a

=

−(a−b)(a−c)(b−c)

−b+c−c+a−b+a

=−

(a−b)(a−c)(b−c)

2a−2b

=−

(a−c)(b−c)

2

Answ

Answer 2

Answer:

0 is your required answer

Step-by-step explanation:

we have a(b-c)+b(c-a)+c(a-b)

=ab-ac+bc-ab+ac-bc

= 0