Question

6. simplify:(v11+v7)(v11-v7).​

Answer 1

$\huge \bf{ \underline{ \underline{Answer}}} \green\downarrow$

$\bf{ \: = > \: 4}$

$\huge \bf{ \underline{ \underline{Explanation}}} \orange\downarrow$

$\bf{( \sqrt{11} + \sqrt{7} )( \sqrt{11} - \sqrt{7} )}$

This is in the form ↓

$\bf{( \: a \: + \: b \: ) \: ( \: a \: - b \: ) \: = \: {a}^{2} \: - \: {b}^{2} }$

$\bf{ \: = >\:( \sqrt{11} \: )^{2} \: - \: ( \: \sqrt{7} \: ) \:^{2}}$

$\bf{ \: = > \: 11 \: - \: 7 \: }$

$\bf{ \: = > \: 4}$

I hope it's helps you.

Please markerd as brainliest answer.

Answer 2

$\huge \bf \pink{ \underline{ \underline{Answer}}} \red\downarrow$

$\bf{ \: = > \: 4}$

$\huge \bf{ \underline{ \underline{Explanation}}} \orange\downarrow$

$\bf{( \sqrt{11} + \sqrt{7} )( \sqrt{11} - \sqrt{7} )}$

This is in the form ↓

$\bf{( \: a \: + \: b \: ) \: ( \: a \: - b \: ) \: = \: {a}^{2} \: - \: {b}^{2} }$

$\bf{ \: = > \:( \sqrt{11} \: )^{2} \: - \: ( \: \sqrt{7} \: ) \:^{2}}$

$\bf{ \: = > \: 11 \: - \: 7 \: }$

$\bf{ \: = > \: 4}$

I hope it's helps you.☺️