Question

6. Simplify: V252 – 5/6 + V294 – 3.​

Answer 1

Answer:

$\sqrt{252}-5\sqrt{6}+\sqrt{294}-3\sqrt{\frac{1}{6}}=6\sqrt{7}+\frac{9}{\sqrt6}$

Step-by-step explanation:

Given:

$\sqrt{252}-5\sqrt{6}+\sqrt{294}-3\sqrt{\frac{1}{6}}$

$=\sqrt{36*7}-5\sqrt{6}+\sqrt{49*6}-3\sqrt{\frac{1}{6}}$

$=\sqrt{36}*\sqrt{7}-5\sqrt{6}+\sqrt{49}*\sqrt{6}-\frac{3}{\sqrt6}}$

$=6\sqrt{7}-5\sqrt{6}+7\sqrt{6}-\frac{3}{\sqrt6}$

$=6\sqrt{7}+2\sqrt{6}-\frac{3}{\sqrt6}$

$=6\sqrt{7}+\frac{2\sqrt{6}\sqrt{6}-3}{\sqrt6}$

$=6\sqrt{7}+\frac{2*6-3}{\sqrt6}$

$=6\sqrt{7}+\frac{12-3}{\sqrt6}$

$=6\sqrt{7}+\frac{9}{\sqrt6}$