6. sinx + sin2x = 0 find value
Answers
Answered by
0
Answer:
Hence
sin
2
x
=
2
sin
x
⋅
cos
x
we have that
sin
x
+
sin
2
x
=
0
⇒
sin
x
+
2
sin
x
cos
x
=
0
⇒
sin
x
(
1
+
2
cos
x
)
=
0
⇒
sin
x
=
0
or
cos
x
=
−
1
2
From
sin
x
=
0
⇒
x
=
k
⋅
π
,
k
∈
N
and
from
cos
x
=
−
1
2
⇒
cos
x
=
cos
(
2
π
3
)
⇒
x
=
2
⋅
k
⋅
π
±
2
⋅
π
3
Answered by
0
Answer:
MARK ME BRAINLIEST PLEASE.
Step-by-step explanation:
sinx + sin2x = 0
sinx + 2sinxcosx = 0
sinx ( 1 + 2cosx) = 0
sin x = 0 => x = 0*
1 + 2 cosx = 0 => cosx = 1/2 => x = 60* or pi/3 radians
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