Question

6 Six pipes can fill a water tank in 18 minutes. Find the time required for 9 pipes to For the tank?​

Answer 1

Answer:

9

Step-by-step explanation:

since equation is inversely proportional

pipe = x

6x = -18 min

x = -18/6

x = -3

so if 1 pipe is added 3 mins get reduced so

if 9 pipes( 3 added to 6 ) are added 9 min get reduced

so 9 pipes can fill it in 9 mins

Answer 2

Given:  Six pipes can fill a water tank in $18$minutes.

We have to find the time required for $9$pipes to fill the tank.

We are solving in the following way:

Let the desired time to fill the tank be $x$minutes.  

In $18$mins, a tank is filled with  $6$pipes

As we know that the lesser the number of pipes more will be the time required by it to fill the tank.

So, this is a case of inverse proportion.

Therefore, $18\times6=x\times9$

$=>x=\frac{18\times6}{9} \\\\=>x=12$

Hence, the time required for $9$pipes to fill the tank is $12$mins.