Question

6. Solve the following sums by using properties.

a) 834 × 101

b) 2 × 9245 × 50

c) 834 + 100 + 76 ​

Answer 1

$a) \red{ Value \:of \: 834 \times 101 }$

$= 834 \times ( 100 + 1 )$

$= 834 \times 100 + 834 \times 1$

/* By Distributive Property */

$\boxed{\pink{a(b+c) = a\times b + a \times c }}$

$= 83400 + 834$

$= 84234$

$\red{ Value \:of \: 834 \times 101 }\green{= 84234}$

$b. \red{ Value \:of \: 2 \times 9245 \times 50 }$

$= (2 \times 50) \times 9245$

$\blue {( Associative \: Property \:under \: Multiplication)}$

$= 100 \times 9245$

$= 924500$

$\red{ Value \:of \: 2 \times 9245 \times 50 }\green{= 924500}$

$c) \red{ Value \:of \: 834 + 100 + 76 }$

$= ( 834 + 76 ) + 100$

$\blue {( Associative \: Property \:under \: addition)}$

$= 910+ 100$

$= 1010$

$\therefore \red{ Value \:of \: 834 + 100 + 76 }$

$\green {= 1010 }$

•••♪

Answer 2

To Find :

Solve the following sums by using properties.

a) 834 × 101

b) 2 × 9245 × 50

c) 834 + 100 + 76

Solution :

a). 834 × ( 100 + 1 )

⇒ 83400 + 834

⇒ 84,234

By distributive property

b). 2 × 9245 × 50

⇒ ( 2 × 50 ) × 9245

⇒ 100 × 9245

⇒ 9,24,500

Associative property

c). 834 + 100 + 76

⇒ ( 834 + 76 ) + 100

⇒ 910 + 100

⇒ 1,010

Associative property