6. Solve the linear equation: 9x+5= 4(x-2)+8
7. Find the T.S.A of a brick whose dimensions are 10cm x 4cm x 3cm.
8. A coin is tossed once. Write all the possible outcomes.
9. In which quadrant the points (-9, 9) will lie.
Answers
Answer:
Step-by-step explanation:
6) 9x +5 = 4(x-2)+8
9x +5 = 4x -8 +8
9x - 4x = -8 +8 -5
5x = -5
x = -5/5
x = -1
7) total surface area of cuboid = 2(l*b +b*h + h*l)
= 2( 10*4 + 4*3 + 3*10)
= 2( 40 + 12 + 30)
= 2 ( 82)
= 164 cm square
8) 2 possible outcomes
1 head , 1 tail
9) second quadrant
Question No. 1:-
Solve the linear equation: 9x+5= 4(x-2)+8
Required Answer:-
Given Equation:-
Question No. 2 :-
Find the T.S.A of a brick whose dimensions are 10cm x 4cm x 3cm.
Required Answer:-
Given:-
Dimension of the brick = 10cm × 4cm × 3cm
Therefore:-
Length = 10cm
Breadth = 4cm
Height = 3cm
To Find :-
T. S. A. of the brick
♡ Solution :-
As we know that,
Substituting the values :-
Hence, T. S. A. of the brick is 162sq.cm
Question No. 3 :-
A coin is tossed once. Write all the possible outcomes.
Required Answer:-
The possible outcomes of a coin if it is tossed once are:-
- Head
- Tail.
Each of these outcomes is equally likely, since there is 1 'head' and 1 'tail' on the coin.
Question No. 4:-
In which quadrant the points (-9, 9) will lie.
Required Answer:-
The point (-9, 9) stands in 2nd quadrant. ( - , +)
N. B. See the attachment for more explanation.