Question

6. Solve: (x - 1)(x - 2)(x +1) = x³


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Answer 1

Answer:

Hope it helps you!!!!!!

Answer 2

Answer:

x = -1 - root 17 / 4 or x = -1 + root 17 / 4

Step-by-step explanation:

[ (x - 1) (x - 2) ] (x + 1) = x^3

[ x (x - 1) - 2(x - 1) ] (x + 1) = x^3

[x^2 - x - 2x + 2] (x + 1) = x^3

(x^2 - 3x + 2) (x + 1) = x^3

x (x^2 - 3x + 2) + 1 (x^2 - 3x + 2) = x^3

x^3 - 3x^2 + 2x + x^2 - 3x + 2 = x^3

- 2x^2 - x + 2 = 0

2x^2 + x - 2 = 0 [ taking (-1) as common ]

{ taking this equation as ax^2 + bx + c = 0, a = 2, b = 1, c = -2 ; and applying the 'completing the square method' , we get }

x = - b _+ root (b^2 - 4ac) / 2a

x = -1 _+ root [ 1^2 - 4*2*(-2) ] / 2*2

x = -1 _+ root ( 1 + 16 ) / 4

x = -1 _+ root 17 / 4

x = -1 - root 17 / 4 or x = -1 + root 17 / 4