(6) Sum of the first 65 terms in am A.P. is 2600 , find the 32 nd term .
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n= 65 , Sn = 2600
Sn= n/2 {2a+(n-1)d } = 2600
65/2 { 2a +(65-1)d } =2600
65 { 2a +64d } = 5200
2a +64d = 5200/65
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