Math, asked by nrameshsi6250, 7 months ago

6 Tan square theta 6 upon cos square theta in answer

Answers

Answered by Bablu067
2

the expression is -6.

Step-by-step explanation:

Consider the provided information.

6\tan^2\theta-\dfrac{6}{\cos^2\theta}6tan

2

θ−

cos

2

θ

6

=6(\tan^2\theta-\dfrac{1}{\cos^2\theta})=6(tan

2

θ−

cos

2

θ

1

)

=6(\tan^2\theta-\sec^2\theta)=6(tan

2

θ−sec

2

θ)

=-6(\sec^2\theta-\tan^2\theta)=−6(sec

2

θ−tan

2

θ)

=-6(1)=−6(1) (∵sec²θ-tan²θ=1)

=-6=−6

Hence, the required value of the expression is -6.

#Learn more

Find the value of 6 tan square A-6 sec square A

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