Math, asked by ahmedmomaya0, 11 hours ago

6 tan² delta-6/cos² delta​

Answers

Answered by vikkiain
0

 - 6

Step-by-step explanation:

6tan^{2}  \delta -  \frac{6}{cos ^{2} \delta }  = 6tan^{2}  \delta - 6sec^{2}  \delta \\  =  - 6(sec^{2}  \delta -tan^{2}  \delta )  =  - 6 \times 1 =  - 6

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