Question

6 tasks and 6 persons. P1 and P2 do not do task T1. T2 is assigned to P3 or P4;. Each person should be assigned with at least 1 task. In how many ways the task can be assigned?
(1 Point)​

Answer 1

P1 and P2 cannot do the task T1, then T1 may be completed in four ways by four persons ( P3,P4,P5,P6)

Task T2 may be completed in two ways by two persons (p3,p4)

The remaining four tasks T3, T4, T5, T6 may be completed in 4! ways such that each person is assigned to atleast one task

Total ways = 4*2*4!= 4*2* 4*3*2*1= 192 =

ways