Question

6. Ten years ago, a father was twelve times as old as his son and ten years hence, he will be twice
as old as his son . Find their present ages.

Answer 1

Answer:

the Present age of the Son = x years the Present age of the Father = y years

Acocording to the Conditions,

y - 10 = 12 (x - 10) - 12x - y = 110. y + 10 = 2 ( x + 10) - 2x - y = -10 .1)

.2)

Subtracting 2) from 1), we get

X = 12

Substituting the value of x = 12 in equation 2), we

get

y = 34

Therefore the Present age of Son and Father is 12 years and 34 years respectively.

Answer 2

Answer:

hey mate ... here is ur answer ...

father's present age = 34 , son's present age = 12

Step-by-step explanation:

Ten years ago father was 12 times as old as his son at that time

Let the age of the son before 10 years =x and age of the father before 10 years =12x

10 years hence he will be twice as old as his son.

2(x+10+10)=(12x+10+10)

⇒2x+40=12x+20

⇒10x=20 

⇒x=2 

⇒ age of son at present=x+10=2+10=12

Age of the father at present=12x+10=122+10=34

hope this will help uh ...

have a great day ahead ....

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