Question

6
${6 }^{2} + 7x + 2$
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Answer 1

Answer:

heya mate ☺

$6x ^{2} + 7x + 2 \\ = 6x ^{2} + (4 + 3)x + 2 \\ = 6x ^{2} + 4x + 3x + 2 \\ = 2x(3x + 2) + 1(3x + 2) \\ = (3x + 2)(2x + 1)$

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Answer 2

➡ 6x² + 7x + 2 = 0

➡ 6x² + 3x + 4x + 2 = 0

➡ 3x(2x + 1) + 2(2x + 1) = 0

➡ (2x + 1)(3x + 2) = 0

➡ 2x + 1 = 0 ; 3x + 2 = 0

➡ 2x = 0 - 1 ; 3x = 0 - 2

➡ 2x = - 1 ; 3x = - 2

➡ x = -1/2 ; x = -2/3

∴ x = -1/2 or -2/3

Step-by-step explanation:

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