Question

6
$6x + \frac{4}3 = 0.28x + 1.16$
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Answer 1

Answer:

here is the answer in the above attachment

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Answer 2

Answer:

Value of x = $\sf{\dfrac{1}{-33}}$

Step-by-step explanation:

Given :

$\sf{6x + \dfrac{4}{3}= 0.28x + 1.16}$

To find :

The value of x

Solution :

$:\implies\sf{6x + \dfrac{4}{3}= 0.28x + 1.16}$

$:\implies\sf{6x-0.28x=\dfrac{1.16}{1}-\dfrac{4}{3}}$

L.C.M. of 1 and 3 is 3 .

$:\implies\sf{5.72x=\dfrac{3.48-4}{3}}$

$:\implies\sf{5.72x=\dfrac{-0.52}{3}}$

$:\implies\sf{x=\dfrac{-0.52}{3}\div\dfrac{5.72}{1}}$

$:\implies\sf{x=\dfrac{\cancel{-0.52}}{3}\times\dfrac{1}{\cancel{5.72}}}$

$:\implies\sf{x=\dfrac{1}{3}\times\dfrac{1}{-11}}$

$:\implies\sf{x=\dfrac{1}{-33}}$

So , the value of x is $\sf{\dfrac{1}{-33}}$ .