Question

6. The 11th term of the AP-5.-5/2.0.5/2.
(a) -20 (1) 20 (0) --30 (d) 30
is​

Answer 1

Step-by-step explanation:

-5, -5/2, 0, 5/2 ......

a = -5

common difference

$d = \frac{ - 5}{2} - ( - 5) \\ = \frac{ - 5}{2} + 5 \\ = \frac{ - 5 + 10}{2} \\ = \frac{5}{2}$

11th term = a + 10d

= -5 + 10(5/2)

= - 5 + 25

= 20

the 11th term is 20

hope you get your answer

Answer 2

GiveN :-

• First term = - 5

• Common difference = - 5/2 - ( - 5 ) = 5/2

• Number of terms = 11

To FinD :-

• 11th term of the given A.P

SolutioN :-

By using A.P formula :

$\large:\implies \boxed{\bf \blue{ A_n = a + ( n-1)d}} \\ \\:\implies \sf A_{11} = - 5 + (11 - 1) \times \frac{5}{2} \\ \\:\implies \sf A_{11} = - 5 + 10 \times \frac{5}{2} \\ \\:\implies \sf A_{11} = - 5 + 5 \times 5 \\ \\:\implies \sf A_{11} = - 5 + 25 \\ \\ :\implies \boxed{ \sf A_{11} = 20}$

$\large \therefore \underline {\bf \green{11th \: term \: of \: AP \: is \: 20}}$