Question

6. The age of a father is twice the square of the
age of his son. Eight years hence, the age of the
father will be 4 years more than three times the
age of the son. Find their present ages.​

Answer 1

Step-by-step explanation:

let son age be x

father's age 2x^2

A.T.Q eight yrs hence

sons age = x+8

father age = 3(x+8) +4

therefore 2x^2+8=3x+24+4

2x^2 -3x -20

2x^2 -8x+5x-20

2x(x-4)+5(x-4)

2x+5=0\ x-4=0

x=-5/2 , x=4

so sons age is 4yrs ,father's age is 32 yrs.

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