Question

6. The angular position of a particle revolving about an
axis is given by e(t) = f - 3t + 4 radian. Find the
acceleration of the point at time t = 2 s. Given
radius of circular path is 1 m.
(2) 1 m/s2
(1) 2 m/s2
(3) 5 m/s2
(4) 5 m/s2

Answer 1

☆points to note before solving:-

1. during motion in circular path..two types os acceleration or forces act on it
2. one is the centripetal acceleration which acts radially towards the centre,responsible for direction and also responsible for circular path of object itself.
3. other is tangential acceleration which acts tangential to the path of object, responsible for change in magnitude of velocity

now let's solve by putting few formulas...□□

see the attachment!! your ans is 1 m/s2

hope it helps..

Good luck ♧♧