6) The area of a circle is 817 cm^2 .Find the length of Arc subtending an angle of 150° at the center.Also find the arc of corresponding sector.
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Step-by-step explanation:
3600 has area=81πcm2
3600 has area=81πcm23000 has area =36081π×300cm2
3600 has area=81πcm23000 has area =36081π×300cm2=3681π×30cm2
3600 has area=81πcm23000 has area =36081π×300cm2=3681π×30cm2=681π×5cm2
3600 has area=81πcm23000 has area =36081π×300cm2=3681π×30cm2=681π×5cm2=6405πcm2
3600 has area=81πcm23000 has area =36081π×300cm2=3681π×30cm2=681π×5cm2=6405πcm2=2135πcm2
3600 has area=81πcm23000 has area =36081π×300cm2=3681π×30cm2=681π×5cm2=6405πcm2=2135πcm22πr (circumference) has →81πcm2 area
3600 has area=81πcm23000 has area =36081π×300cm2=3681π×30cm2=681π×5cm2=6405πcm2=2135πcm22πr (circumference) has →81πcm2 areaor 81πcm2 area →2πr are length
3600 has area=81πcm23000 has area =36081π×300cm2=3681π×30cm2=681π×5cm2=6405πcm2=2135πcm22πr (circumference) has →81πcm2 areaor 81πcm2 area →2πr are length⇒ Length of arc =1622πr×135
3600 has area=81πcm23000 has area =36081π×300cm2=3681π×30cm2=681π×5cm2=6405πcm2=2135πcm22πr (circumference) has →81πcm2 areaor 81πcm2 area →2πr are length⇒ Length of arc =1622πr×135πr2=81cm2
3600 has area=81πcm23000 has area =36081π×300cm2=3681π×30cm2=681π×5cm2=6405πcm2=2135πcm22πr (circumference) has →81πcm2 areaor 81πcm2 area →2πr are length⇒ Length of arc =1622πr×135πr2=81cm2⇒r=π81
3600 has area=81πcm23000 has area =36081π×300cm2=3681π×30cm2=681π×5cm2=6405πcm2=2135πcm22πr (circumference) has →81πcm2 areaor 81πcm2 area →2πr are length⇒ Length of arc =1622πr×135πr2=81cm2⇒r=π81∴ Length of arc corresponding to 3000 angle =162270ππ81
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