Question

6. The area of a trapezium is 729 cm² and the distance between the two parallel sides is 18 cm.
one of its parallel sides is 3 cm shorter than the other parallel side, then find the length of its
parallel sides.​

Answer 1

Answer:

39 cm , 42 cm

Step-by-step explanation:

trapezium can be divided into three parts, one rectangle , two right angle triangles. this can be obtained by joining to vertices at parallel sides.

now, area of trapezium = area of that rectangle + 2 area of right angled triangle

729 = length * breadth + 2( 1/2 base *height)

length of the rectangle will be shortest of parallel side, let it be X.

breadth of rectangle = distance between parallel sides= 18

height of right angled triangle = distance between parallel sides= 18

base of triangle = 1/2 ( difference between two parallel sides) =3/2

now, 18x + 3/2 *18 = 729

18x + 27 = 729

18x = 702

X = 702/18 = 39 cm

so, smallest parallel side = 39 cm

another parallel side = 39+3 = 42 cm