6. The base of an isosceles triangle is 40 cm and
its area is 420 cm. Find the length of its equal
sides.
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Answer: Let ABC be the isosceles triangle.
Area of triangle = 1/2 base x height
⇒height = 2 x area / base
⇒height = 21 cm
→Let BC be the base and AB and AC be the equal sides of the triangle .
→Let D be the point where height meets the base BC .
→D will be the mid-point of ABC because its isosceles triangle.
⇒Given AB = AC = √(21)² + (20)² [∵ hypotenuse of triangle ADB and ADC ]
⇒ = √441 + 400
⇒ = √841
⇒ = 29 cm
∴The length of its equal sides of triangle ABC = 29 cm
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