Question

6.
The brakes applied to a car produces an acceleration of 6 m/s in the opposite direction to th
motion. If the car takes two seconds to stop after the application of brakes, calculate the distanc
it travels during this time.​

Answer 1

Answer:

Given:

Accerleration: a=−6 m/s

Time t=2 s

Final velocity, v=0 m/s

v=u+at

0=u−6×2

u=12 m/s

s=ut+1/2at^2

s= 12×2+1/2×(-6)×2^2

s = 24+(-6)×2×2/2

s= 24+(-6)×2

s= 24-12

s=12m

distance travelled by car is 12m

s = 12m