Question

6. The centre of a cirde is 42). If one end of the diameter of the circle is (-3. 7) then
find the other end.​

Answer 1

Step-by-step explanation:

${\underline{\boxed{ \purple{ \maltese \: {\textsf{\textbf{\purple{question}}}}}}}}$

6. The centre of a cirde is 42). If one end of the diameter of the circle is (-3. 7) then

find the other end.

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The other end is (-5,-3).

Since we have given that

Centre of circle = (-4,2)

One end of diameter of circle = (-3,7)

Let the other end of circle be (x,y).

As we know that centre is the mid point of diameter.

So, it becomes,

$\frac{ - 3 + x}{2} \: \frac{7 + y}{2} = (- 4 \: - 2)$

Cᴏᴍᴘᴀʀɪɴɢ ʙᴏᴛʜ ᴛʜᴇ Tᴇʀᴍs,

$\frac{ - 3 + x}{2} = - 4$

$- 3 + x = - 8$

$x = - 8 + 3 \\ = - 5$

Sɪᴍɪʟᴀʀʟʏ,

$\frac{7 + 4}{2} = 2$

$7 + y = 4$

$y = 4 - 7 \\ = - 3$

Sᴏ, Tʜᴇ Oᴛʜᴇʀ Eɴᴅ ᴡɪʟʟ ʙᴇ (-5,-3)

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