Question

6. The correct factors of 27a3−64b9 are _____.


a.
(3a−4b3)(9a2−24ab3+16b6)


b.
(3a−4b3)(9a2+12ab3+16b6)


c.
(3a−4b3)(9a2+16b6)


d.
None of these

Answer 1

Answer:

=(3a−4b)(9a2+12ab+16b2)

Step-by-step explanation:

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