Question

6. The density of water is 1 g/cc. Ice floats on water with 90% of its volume inside the water
What will be the mass of a cube of ice of side 3 cm?
A.27 g
B. 30 g
C. 24.3 g
D. the data is insufficient)​

Answer 1

Answer:

24.3 g

Explanation:

According to Archimedes principle, buoyant force = weight of liquid displaced Density of the object floating in a liquid = density of the liquid * fraction of the object inside the liquid Mathematically represented thus: ρ(object) = ρ(water) * fraction f ρ(water) = 1 g/cc, fraction of the object inside the liquid  = 10% = 0.1 ρ(object) = 1 × ( 1 — 0.1 ) = 0.9 g/cc ρ(object) = 0.9 g/cc   To get the mass of a cube of ice, we use the formula M = ρV ρ = 0.9 g/cc , L = 3cm, V = L^3 = 3^3 = 27 cc M = 0.9 * 27 M = 24.3 g

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Answer 2

Answer:

The mass of a cube of ice is 24.3 g

The correct option is Option (C)

Explanation:

• According to Archimedes principle, buoyant force = weight of liquid displaced
• Density of the object floating in a liquid = density of the liquid * fraction of the object inside the liquid
• Mathematically represented thus: ρ(object) = ρ(water) * fraction f ρ(water) = 1 g/cc,
• fraction of the object inside the liquid  = 10% = 0.1 ρ(object) = 1 × ( 1 — 0.1 ) = 0.9 g/cc ρ(object) = 0.9 g/cc  
• To get the mass of a cube of ice, we use the formula
• M = ρV ρ = 0.9 g/cc ,
• L = 3cm,
• V = L^3 = 3^3 = 27 cc M = 0.9 * 27 M = 24.3 g