Question

6. The digit at ten' place of a two digit number is four times the digit at unit's place. If the sum of
this number and the number formed by reversing the digits is 55. Find the number.​

Answer 1

Answer:

Let the digits in the ten's and ones place of the required number be x and y respectively.

Given ,

x=4y

Since we do not know the OG number ,

we will assume the number to be 10x + y

Interchanged number = 10y + x

Also given,

10x+y + 10y+x =55

10x+x + 10y+y = 55

11x +11y=55

11 (x+y)=55

x+y = 55/11

x+y =5

4y+y = 5

5y = 5

y = 1

x =4x = 4

The number = xy = 41

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tq for asking.