Question

6. The digit at the ten's place of a two digit number
is four times that in the unit's place. If the digits
are reversed, the new number will be 54 less than
the original number. Find the original number.
Check your solution.​

Answer 1

Answer:

Step-by-step explanation:

Let us take the digit at the ten's place as X and digit at one's place as Y.

given: x = 4y

original number= 10x+y or 41y (x=4y)

reversed number = (10y +x)  or 14 y

as 10y +x is 54 less than 10x+y, we can say

41y - 14y = 54

27y = 54

therefore, y = 54/27

                    = 2

therfore, y = 2

since x = 4y, x=8

therefore the original number is 82 and the reverse is 28.

we can check the solution by subtracting the two:

82-28 = 54

as the condition holds, answer is verified.

HOPE THIS HELPS

Answer 2

Step-by-step explanation:

Hope it may help you...

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