Question

6. The Energy of radiation having frequency (1 × 1014)Hz is

Answer 1

Explanation:

$energy \: = plancks \: constant \: ( \: h \: ) \: \times frequency \: ( \: f \: ) \:$

E = hf

= 6.626 × 10 ^-34 × ( 1 × 1014 )

= 6.718 × 10^-31 J