Question

6. The equation 2x2 + kx + 3 = 0
has two equal roots, then the
value of kis
O (a) 1/6
O (b) + 4
O (c) +312
0 (d) +216​

Answer 1

Required Answer:-

Given:

• The equation 2x² + kx + 3 = 0 has two equal roots.

To find:

• The values of k.

Solution:

We have,

➡ 2x² + kx + 3 = 0

Here,

1. a = 2
2. b = k
3. c = 3

★ We know that roots of a quadratic equation are equal if and only if the discriminant is equal to zero.

So, according to the given condition,

➡ k² - 4 × 2 × 3 = 0

➡ k² - 24 = 0

➡ k² = 24

➡ k = √24

➡ k = ±2√6

Hence, the values of k satisfying are 2√6 and -2√6

Answer:

• The values of k are 2√6 and -2√6

Answer 2

Answer:

Given.

2×2+kx+3

here it is the form ax^2+bc+c = 0

here a=2 , b= k , c= 3

if it it have two equal to root than /_ = 0

☆ b^2-4ac = 0

☆ k^2-4 (2) (3)=0

☆ k^2-24=0

☆ k=24

☆ k= 6²

Step-by-step explanation:

hope you understand this answers