Question

6. The equation to the locus of a point 'p' for which the distance from 'p' to (2, 3) is double the distance from 'p' to x-axis is [ ] 1) +3y-4-6y +13=0 2) 2 - 3 - 4x-6y +13 - 0 3) 2-3y 4x+6y-130 x+3y + 4+ 6y-13=0?

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Answer 1

Step-by-step explanation:

+3y-4-6y +13=0

2 - 3 - 4x-6y +13 - 0

hope it helps

Answer 2

Step-by-step explanation:

Let P(x,y) be an arbitrary point in X−Y plane.

Therefore distance of P from A(0,5) is

PA=

x

2

+(y−5)

2

...(i)

And distance of P from y axis.

d

y

=∣x∣

It is given that

2d

y

=PA

Or

2∣x∣=

x

2

+(y−5)

24x 2 =x 2+(y−5) 23x 2 −(y−5) 2 =03x2−y2+10y−25=0