Physics, asked by yuvrajdhamija02, 10 months ago

6. The far point of a myopie person
a myopie person is 80 cm in front of the eye. What is the na
power of the lens required to correct the problem?
om how hwnermetropia is corrected. The near point of

Answers

Answered by subinkumar5u

1

Answer:

-1.25 D

Explanation:

D=1/F

A/q F= -0.8m

so. D=-1/0.8

= -1.25D

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