Question

6. The figure shows a triangle STU where TU= 11 cm.
of the length of HU and ZSHU = 90°. Given that
ADVANCED LEVEL
here
and H lies on TU such that the length of TH is 120%
the area of ASTH is 21 cm, find ZTSU.
S
Trigonom
the dista
bodies
T
H
U
proble
11 cm​

Answer 1

Answer:

Juhi Chawla and detergent sodium hydroxide is