Question

6) The first and the last term of an arithmetic progression are 1 and 15 respectively. If the sum of all the terms of the progression is 64, then the number of terms in the progression are ?​

Answer 1

Answer:

n=8

Step-by-step explanation:

a=1        l=15      S=64

S= n\2[a+l]

64=n\2[1+15]

64=n\2[16]

64=n[8]

n=64/8

n=8

Answer 2

Step-by-step explanation:

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