Math, asked by preetuak, 10 months ago

6.
The floor of a big hall is in
share of a square of a side
side 8m. The flood is to be
covered by square tiles each of
40cm. Find the number
of tiles required. Also find the
- Cost of teling the hall if each
side tile costs rs 12.​

Answers

Answered by KamaldevSharma
7

Answer:

no. of tiles required =400

total cost=4800rupees

Step-by-step explanation:

area of floor=800×800=640000cm²

area of tile=40×40=1600cm²

no. of tiles required =640000/1600=6400/16=400

total cost=400×12=4800rupees

Please mark as brainliest

Answered by MяƖиνιѕιвʟє
6

AnSwEr :-

  • Number of tiles = 400

  • Total cost = 4800

GiVeN :-

  • Length of side(A) of hall (Square) = 8m = 8 × 100 = 800cm

  • Side(a) of tiles (Square) = 40 cm

  • Cost of Each tile = 12

To FiNd :-

  • Number of Tiles required to cover the hall

  • Cost of Tiles to cover the floor

SoLuTiOn :-

We know that,

  • Area of Square = A^2

So,

Area of Hall = 800 × 800 = 640000 cm^2

Now,

  • Area of Each Tile = a^2

=> 40 × 40 = 1600 cm^2

  • Number of Tiles = Area of Hall / Area of a Tile

No of Tiles = 640000 / 1600 = 400

Now,

Cost of All tiles to cover the floor at ₹ 12 each is

=> 400 × 12 = 4800 ₹

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