6.
The floor of a big hall is in
share of a square of a side
side 8m. The flood is to be
covered by square tiles each of
40cm. Find the number
of tiles required. Also find the
- Cost of teling the hall if each
side tile costs rs 12.
Answers
Answered by
7
Answer:
no. of tiles required =400
total cost=4800rupees
Step-by-step explanation:
area of floor=800×800=640000cm²
area of tile=40×40=1600cm²
no. of tiles required =640000/1600=6400/16=400
total cost=400×12=4800rupees
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Answered by
6
AnSwEr :-
- Number of tiles = 400
- Total cost = 4800 ₹
GiVeN :-
- Length of side(A) of hall (Square) = 8m = 8 × 100 = 800cm
- Side(a) of tiles (Square) = 40 cm
- Cost of Each tile = 12 ₹
To FiNd :-
- Number of Tiles required to cover the hall
- Cost of Tiles to cover the floor
SoLuTiOn :-
We know that,
- Area of Square = A^2
So,
Area of Hall = 800 × 800 = 640000 cm^2
Now,
- Area of Each Tile = a^2
=> 40 × 40 = 1600 cm^2
- Number of Tiles = Area of Hall / Area of a Tile
No of Tiles = 640000 / 1600 = 400
Now,
Cost of All tiles to cover the floor at ₹ 12 each is
=> 400 × 12 = 4800 ₹
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