Question

6. The following table shows the blood groups of 30 students of a class.
Blood group
B
A
o
AB
Number of students
9
7
11
3
One student of the class is chosen at random. What is the probability that the chosen studen
has the blood group a. A and b. AB?
boys and the res​

Answer 1

Answer:

a.7/30

b.3/30

Step-by-step explanation:

Total =9+7+11+3

P(A)=7/30

P(AB)=3/30

Answer 2

Answer:

a. 7/30

b. 1/10

Step-by-step explanation:

Total population = 3+7+9+11 = 30

$probability \: = \: \frac{number \: of \: favorable \: events}{total \: number \: of \: evemts}$

(a)

Here, the no. of favourable events = 7 (As there are 7 'A' blood group students)

Total no. of events = 30

So, the probability = 7/30

(b)

Here the no. of favourable events = 3 (As there are 3 'AB' blood group students)

Total no. of events = 30

So, the probability = 3/30 = 1/10