Question

6.
The force on a body executing SHM is 4 N when
the displacement from mean position is 2 cm. If
amplitude of oscillation is 10 cm, then the
maximum kinetic energy associated with the SHM
will be
[NCERT Pg. 351]
f 1 J
(2) 4J
(3) 2 J
(4) 3 J​

Answer 1

Answer:

F=k×x

2=k×2×10

−2

k=100

TE=

2

1

KA

2

TE=

2

1

100×(5×10

−2

)

2

=0.125J