Question

6. The largest number which divides 377 286 and 421 leaving remainders 9, 10 and 7 respectively, is: ​

Answer 1

Step-by-step explanation:

• 377 - 9 = 368
• 286 - 10 = 276
• 421 - 7 = 414

So, the new no. are => 368 , 276 , 414

then, find the H.C.F of 368 and 276

Then again Find the H.C.F of the answer and 414

So, this is Method

Hope it's Understand ..

Answer 2

SOLUTION

TO DETERMINE

The largest number which divides 377 286 and 421 leaving remainders 9, 10 and 7 respectively

TO DETERMINE

Here the required number is the largest number which divides 377 286 and 421 leaving remainders 9, 10 and 7 respectively

Hence the required number is the largest number which divides ( 377 - 9 ) , ( 286 - 10 ) and ( 421 - 7 ) completely

In other words the required number is the largest number which divides 368 , 276 and 414 completely

We have to find the HCF of 368 , 276 and 414

Here the given numbers are 368 , 276 and 414

368 = 2 × 2 × 2 × 2 × 23

276 = 2 × 2 × 3 × 23

414 = 2 × 3 × 3 × 23

HCF

= 2 × 23

= 46

FINAL ANSWER

46 is the largest number which divides 377 286 and 421 leaving remainders 9, 10 and 7 respectively

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

$1.$ If HCF of two numbers be 40 then which of the following cannot be their LCM.

https://brainly.in/question/28609013

2. The HCF and LCM of two numbers are 17 & 1666 respectively. if one of the numbers is 119 find the other

https://brainly.in/question/13812250