Question

6. The length (16 cm) and area of cross section
(4 cm) of a copper wire
are increased by 25% each
If the resistance of original wire is 8 , find the new
resistance​

Answer 1

Explanation:

HEY MATE.........

$l = 16cm = 16 \times {10}^{ - 2} m \\ \\ a = 4 {cm}^{2} = 4 \times {10}^{ - 4} m \\ \\ r = 8 \\ \\ r = rho \frac{l}{a} = 8ohm \\ \\ r(new) = rho \frac{(1.25)l}{a(1.25)} \\ \\ = rho \frac{l}{a} = 8ohm \\ \\ \\ new \: resistance \: is \: also \: 8ohm$

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