Math, asked by realAtul, 10 months ago

6. The length of a rectangle is three times its width and the length of its diagonal is 6/10 cm
The perimeter of the rectangle is
(a) 48 cm
(b) 36 cm
(c) 24 cm
(d) 24/10 cm

Answers

Answered by krishnakakkar12
2

Answer:

Given [l=3b]

In ΔABC

AC

2

=b

2

+l

2

360=10b

2

b

2

=36

[b= 6 cm] & [l= 18 cm]

Perimeter of rectangle = 2[l+b]

=2[6+18]

=2×24

perimeter = 48 cm

Answered by Nishika20
0

Answer:

=Given [l=3b]

In ΔABC

AC

2

=b

2

+l

2

360=10b

2

b

2

=36

[b= 6 cm] & [l= 18 cm]

Perimeter of rectangle = 2[l+b]

=2[6+18]

=2×24

perimeter = 48 cm

Step-by-step explanation:

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